c^2-3c-18=0

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Solution for c^2-3c-18=0 equation:


Simplifying
c2 + -3c + -18 = 0

Reorder the terms:
-18 + -3c + c2 = 0

Solving
-18 + -3c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -1c)(6 + -1c) = 0

Subproblem 1

Set the factor '(-3 + -1c)' equal to zero and attempt to solve: Simplifying -3 + -1c = 0 Solving -3 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1c = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1c = 0 + 3 -1c = 0 + 3 Combine like terms: 0 + 3 = 3 -1c = 3 Divide each side by '-1'. c = -3 Simplifying c = -3

Subproblem 2

Set the factor '(6 + -1c)' equal to zero and attempt to solve: Simplifying 6 + -1c = 0 Solving 6 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-6' to each side of the equation. 6 + -6 + -1c = 0 + -6 Combine like terms: 6 + -6 = 0 0 + -1c = 0 + -6 -1c = 0 + -6 Combine like terms: 0 + -6 = -6 -1c = -6 Divide each side by '-1'. c = 6 Simplifying c = 6

Solution

c = {-3, 6}

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